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x^2-12.5x-3.5=0
a = 1; b = -12.5; c = -3.5;
Δ = b2-4ac
Δ = -12.52-4·1·(-3.5)
Δ = 170.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12.5)-\sqrt{170.25}}{2*1}=\frac{12.5-\sqrt{170.25}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12.5)+\sqrt{170.25}}{2*1}=\frac{12.5+\sqrt{170.25}}{2} $
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